Answer:
90
Step-by-step explanation:
divide 292 by 2
subtract 56 to get Ali's and add 56 to his Dad's
I could be wrong it's 6 am
Answer:
Width = 15 feet
Length = 45 feet
Step-by-step explanation:
You need to fence in a rectangular piece of land for your dog to run and play. The length is 3 times the width. If the perimeter is 120 ft, what are the dimensions of your very own dog park?
Perimeter of a rectangle = 2L + 2W
The length is 3 times the width.
L = Length = 3W
W = Width
P = 120 ft
Hence:
120 = 2L + 2W
120 = 2(3W) + 2W
120 = 6W + 2W
120 = 8W
W = 120/8
W = 15 feet
Solving for Length
L = 3W
L = 3 × 15 feet
L = 45 feet
Therefore, the dimensions of your very own dog park is
Width = 15 feet
Length = 45 feet
Answer:
68.4 meters shorter
Step-by-step explanation:
ok so you want to compare the distance 80 m + 270 m with the diagonal length.
the diagonal length = root ( 80^2 + 270^2 )
diagonal length = root(6400 + 72900)
diagonal = root(79300) =281.602 m
so.
350 - 281.602 = 68.397 meters about 68.4 meters shorter than walking around
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
