Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
y=1x+-1
Step-by-step explanation:
y=mx+b
m=slope which is 1/1 because it is rise over run (rising 1, running 1)
b=y-intercept form which is -1 because that is where the line meets the y axis
Your answer is 7.
I subtracted 5 from 12 to find the missing number for KL that is 7.
Therefore, your answer is 7
Answer:
THEY DIDN'T IT WAS BECAUSE THEY MADE UP A FAKE RUMER AND HAD TO MAKE IT LOOK REAL
Step-by-step explanation:
Answer:
+2633 ft
Step-by-step explanation:
The city is above sea level meaning it is a positive number.
