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tankabanditka [31]
4 years ago
6

I have to place them in order.m

Mathematics
1 answer:
julsineya [31]4 years ago
7 0

Answer:

1. 4.5 (9/2)

2. 5.2 (square root of 27)

3. 5.8

4. 6.3 (2pi)

Step-by-step explanation:

The square root of 27 is 5.2, 2pi is 6.3, and 9/2 is 4.5. So the first one is 4.5. The second one is 5.2. The third one is 5.8 and the fourth one is 6.3. I hope this helps! Please mark me brainliest!

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The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
Create an Expression that can be rewritten as 4^5
BigorU [14]
4 x 4 x 4 x 4 x 4

I think that’s the answer
3 0
3 years ago
Solve using the substitution method 2x+3y=1 y=x-8
QveST [7]
Subsitute

y=x-8
since y=x-8, subsitute x-8 for y

2x+3(x-8)=1
distribute (a(b+c)=ab+ac)
3(x-8)=3x-24

2x+3x-24=1
combine like terms
5x-24=1
add 24 to both sides
5x=25
divide 5
x=5
subsitute
y=x-8
y=5-8
y=-3

x=5
y=-3 is solution
in (x,y) forom
(5,-3) is the solution
7 0
3 years ago
Read 2 more answers
Please help, quick math, and a short explanation on how you got the answer! Thank you!!
Lostsunrise [7]

Answer:

this is an iscoceles triangle.

I know this because 2 of the sides are equal in length

Therefore,

AB=AC

3x-5=-2x+15

x-5=15

x=20

if x=20 then BC=2(20)

BC=40

Step-by-step explanation:

4 0
3 years ago
What is the slope of the line that passes through the points (-5,9) and (5,11)?
Minchanka [31]
The slope is 1/5


I hope this helps!!!!
4 0
3 years ago
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