Please help ASAP I need done. Thanks

Mathematics

2 answers:

Irina18 [472]1 year ago

7 0

Answer:

man what is this....I haven't learnt this one yet

DiKsa [7]1 year ago

6 0

Rise=4 Run=1. Therefore, the slope is -4/1, or negative four over one. It is decreasing, down four, one right.

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The average number of points you scored in the first 9 basketball games of the season was 23. What do you need in the 10th game

Vlada [557]

Answer:

B. 10n-207

Step-by-step explanation:

Given,

The average number of points of 9 games = 23,

∵ Sum of observations = their average × number of observations

So, the total points for 9 games = 9 × 23 = 207,

Now, if the average of 10 games is n,

Then the total points for 10 games = 10n,

Hence, the number of points earned in 10th game = the total points for 10 games - the total points for 9 games

= 10n - 207

i.e. OPTION B is correct.

3 0

2 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$