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kati45 [8]
2 years ago
9

When Brooklyn runs the 400 meter dash, her finishing times are normally distributed with a mean of 76 seconds and a standard dev

iation of 3 seconds. Using the empirical rule, what percentage of races will her finishing time be between 70 and 82 seconds?
Mathematics
1 answer:
KonstantinChe [14]2 years ago
3 0

Using the Empirical Rule, it is found that her finishing time will be between 70 and 82 seconds in 95% of her races.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, the mean is of 76 seconds and the standard deviation is of 3 seconds, then:

76 - 2 x 3 = 70.

76 + 2 x 3 = 82.

Which means that values between 70 and 82 seconds are within 2 standard deviations of the mean, hence the percentage is of 95%.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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Willy rents a bike for 7 days. The charge is $15 plus the $0.08 per mile. He wants to spend exactly $35. How many miles can he r
Burka [1]

Answer:

Willy can ride the bike for 250 miles.

Step-by-step explanation:

$35 - $15 = $20

$0.08 × 12.5 = $1

$1 per 12.5 miles

$20 × 12.5 = 250

3 0
3 years ago
Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

3 0
3 years ago
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Factor the expression by finding the GCF. 16m2 − 12m
ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m  or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

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3 years ago
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Answer:

Question 9:

The product is irrational

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20

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Step-by-step explanation:

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3 years ago
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Answer:

ASA

Step-by-step explanation:

I think is Asa because it means when any two angles and their included sides are equal in both triangles.

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