Answer:
Step-by-step explanation:
bx-c=ax+d
<=> bx-ax=c+d
<=> (b-a)x=c+d
<=> x=(c+d)/(b-a)
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0
Thus,
The equations he must solved now is k^2-8+12=0
The THIRD statement is not true.
$2000 (spends a month)
The 5% of $2000 is only $100 for food.
The first statement is true "The household spend $260 per month on the car".
13 % of $2000 = $260
The second statement is true "The household spend $600 per month for rent".
30% of $2000 = $600
The fourth statement is also true "The household spend $200 in savings each month"
10% of $2000 = $200
What I did was trial and error. (There is a mathematical way to do this but...)
so you have 10*12 and that equals 120. That is the area of the photo. With the frame, the area is 288.
Increase each number as so:
11*13=143.......continue trial and error
16*18=288
answer: 16
Hope that helps!
