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ladessa [460]
3 years ago
11

Which function's graph has x-intercepts at x=−1 and x=3, and a vertex at point (1,−4)?

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

Top right option: g(x) = (x+1)(x-3)

Step-by-step explanation:

x=-1 is the solution to x+1=0

x=3 is the solution to x-3=0

Therefore, your expression so far is (x+1)(x-3) or x²-2x-3.

Since the vertex must be (1,-4) we must check if x=1 satisfies the equation x=-b/2a:

x=-b/2a

1=-(-2)/2(1)

1=2/2

1=1

Both sides are equal to each other, so the final function is g(x) = (x+1)(x-3)

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