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Whitepunk [10]
3 years ago
13

What is the sum of a-1/abc^3 + 3-b/abc^3

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0
The answer is\frac{a-b+2}{abc^{3} }

The expression is \frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} }

Since \frac{a}{x} + \frac{b}{x} = \frac{a+b}{x}, then:

\frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} } = \frac{a-1+3-b}{abc^{3} }= \frac{a-b-1+3}{abc^{3} }=\frac{a-b+2}{abc^{3} }
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Hey there! I’m happy to help!

We see that the two equal sides are longer than the base. This means that our a will be larger than b. The problem says that one of the longer sides is 6.3. Since the two longer sides are equal, that means that both longer sides are 6.3 cm. Therefore, we can simply subtract these two from the perimeter to find the shorter side, which is the base.

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kotegsom [21]
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