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Whitepunk [10]
2 years ago
13

What is the sum of a-1/abc^3 + 3-b/abc^3

Mathematics
1 answer:
Lyrx [107]2 years ago
4 0
The answer is\frac{a-b+2}{abc^{3} }

The expression is \frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} }

Since \frac{a}{x} + \frac{b}{x} = \frac{a+b}{x}, then:

\frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} } = \frac{a-1+3-b}{abc^{3} }= \frac{a-b-1+3}{abc^{3} }=\frac{a-b+2}{abc^{3} }
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1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

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3 years ago
What is the Domain, Range, and the vertex for this graph?
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Answer:

Step-by-step explanation:

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Use the data in the table to complete the sentence.
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x is plus 1 and y is minus 1.

Step-by-step explanation:

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