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choli [55]
2 years ago
10

What does a "swivel chair" work task involve?

Computers and Technology
1 answer:
nadezda [96]2 years ago
4 0

Answer:

An employee literally swings from application to application to accomplish the laborious task of manually copying information from one application, validating it, and pasting it in another application. In applying human judgment and decision making: Entering data multiple times into different applications. Ensure that complex information obtained from an application is accurate. Communicate physicallly with a group of people simultaneously.

Explanation:

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What is the iterative procedure of recursive and nonrecursive?
DanielleElmas [232]

Answer:

nonrecursive

Explanation:

3 0
3 years ago
Which of the following is not a benefit of normalization?
mixer [17]

Answer:

The answer is option (4) Maximize redundancy as normalization minimizes redundancy of data.

Explanation:

Normalization of databases leads to minimization of data redundancy in databases. It doesn't maximize data redundancy. Data redundancy leads to wastage of resources. Normalization of databases minimizes insertion anomolies. Normalization of databases minimizes deletion anomolies. Normalization of databases minimizes updation anomolies.  So , the answer to the question is option (4) maximize redundancy.

8 0
3 years ago
In 2009 to 2010, how many social network users were reported as being victims of online abuse?
Dafna1 [17]
The answer is B because being victims of online abuse is not important
7 0
3 years ago
Read 2 more answers
Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0
3 years ago
Define a function SetTime, with int parameters hoursVal and minutesVal, that returns a struct of type TimeHrMin. The function sh
Lapatulllka [165]

Answer:

#include <stdio.h>

typedef struct TimeHrMin_struct //struct

{

int hours;

int minutes;

} TimeHrMin;

struct TimeHrMin_struct SetTime(int hoursVal,int minutesVal) //SetTime function

{

struct TimeHrMin_struct str;

str.hours=hoursVal; //assigning the values

str.minutes=minutesVal;

return str; //returning the struct

}

int main(void)

{

TimeHrMin studentLateness;

int hours;

int minutes;

scanf("%d %d", &hours, &minutes);

studentLateness = SetTime(hours, minutes); //calling the function

printf("The student is %d hours and %d minutes late.\n", studentLateness.hours, studentLateness.minutes);

return 0;

}

Explanation:

4 0
3 years ago
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