A recipe for deducing the square root involves guessing a starting value for y. Without another recipe to be told how to pick a
1 answer:
You might be interested in
Answer:
Check the explanation
Explanation:
CREATE FUNCTION dbo.DateRange_sp4 ("at"StartDate DATE, "at"NumberofConsecutivedays INT) RETURNS "at"DateList TABLE ( DateID INT IDENTITY, DateValue DATE, Year SMALLINT, Quarter SMALLINT, Month SMALLINT, Week SMALLINT, DayOfWeek SMALLINT ) AS BEGIN DECLARE "at"Counter INT = 0; WHILE ("at"Counter < "at"NumberofConsecutivedays) BEGIN INSERT INTO "at"DateList VALUES ("at"Counter + 1, DATEADD(DAY, "at"Counter, "at"StartDate), DATEPART(YEAR, "at"StartDate), DATEPART(QUARTER, "at"StartDate), DATEPART(MONTH, "at"StartDate), DATEPART(WEEK, "at"StartDate), DatePart(WEEKDAY, "at"StartDate) ); SET "at"StartDate = DATEADD(day,"at"Counter + 1, "at"StartDate); SET "at"Counter += 1 END RETURN; END GO SELECT * FROM dbo.DateRange_sp4('2020-01-10', 20);
kindly check the screenshot below
Answer:
The output is 24
Explanation:
Given
The above code segment
Required
The output
We have (on the first line):
On the second line:
Substitute the value of each variable
Solve the inner brackets
8%3 implies that, the remainder when 8 is divided by 3.
The remainder is 2
So:
<em>Hence, the output is 24</em>