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Aleksandr [31]
2 years ago
6

PLS HELP ME ASAP I WiLL MARK THE BRAINLIEST

Mathematics
1 answer:
Fittoniya [83]2 years ago
4 0

Answer:

1400 is the volume and the surface area 980

Step-by-step explanation:

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Which of the following is a horizontal stretch of the parent function?
melisa1 [442]

Answer:

C.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Slade draws triangle PQR. He then constructs a perpendicular bisector from vertex P that intersects side QR at point T. What can
AVprozaik [17]

Answer:

QT = RT

Step-by-step explanation:

When drawing triangle PQR the perpendicular bisector cuts the triangle in half, which results in two sides that are congruent. This makes QT and RT congruent.

3 0
3 years ago
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it takes 47 minutes for 7 people to paint 7 walls. how many minutes does it take 20 people to paint 20 walls?
4vir4ik [10]

Answer:

7 people, 7 walls, 48 minutes

 

Each person paints 1 wall in 48 minutes

 

20 persons, 20 walls


Each person can paint 1 wall in 48 minutes so it will  take 48 minutes.



6 0
3 years ago
Please rewrite 5x − 15y = − 60 in the slope intercept form
Margarita [4]
Basically solve for y
minus 5x fromboth sides
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4 0
3 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
3 years ago
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