The given scale for the map means that a distance of 1 cm between two locations on the map corresponds to a real distance between them of 600,000 cm = 6 km.
So, if the distance between two places in reality is 87 km, on the map this would be represented by a distance of 14.5 cm, since
87 = 84 + 3
87 = 6 • 14 + 6 • (1/2)
87 = 6 • (14 + 1/2)
-3(x+5)=-9
-3x-15=-9
+15 +15
-3x=6
-1x=2
1x=-2
x=-2
Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

In the given case, you have:
A = 4
T = 3π/4
b = -3
By replacing you obtain:

Hence, the answer is:
f(x) = 4cos(8/3 x) - 3
1.
18 units
10 units right and 8 units up.
2.
7 units
3 units right and 4 units down.
3.
8 units
1 units right and 7 units down
4.
8 units
5 units and 3 units down
Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)