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Otrada [13]
1 year ago
13

Part A Divide. 6,499 - 7 =

Mathematics
1 answer:
Ksenya-84 [330]1 year ago
7 0

Answer:0

Step-by-step explanation:

0

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A team spent 20 mins on passing drills and 40 minuets ona shooting drill, what is the ratio of time spent on shooting drills to
aliya0001 [1]
20 minutes on passing .....40 minutes on shooting

ratio of time spent on shooting to passing....
these are not hard, u just have to pay attention to the wording...

the ratio of shooting to passing is 40/20 which reduces to 2/1 or 2:1 or
2 to 1 <===

but if it would have asked for passing to shooting, it would have been :
20/40 which reduces to 1/2 or 1:2 or 1 to 2

so ur answer is 2/1 or 2:1 or 2 to 1
6 0
3 years ago
Factor 5x^2+26x+24 ?
SashulF [63]
First u add all of them and then multiple 2 numbers then theres ur answer
4 0
3 years ago
How do you change inches to meters
zimovet [89]

Answer:

there are 39.3701 inches in a meter if it is asking how many inches are in blank meters do the number of meters times the number i mentioned earlier

hoped this helped, have a nice day

Step-by-step explanation:

5 0
3 years ago
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
Find the measure of side b.
malfutka [58]
I think it’s 236.8 correct me if I’m wrong?
7 0
2 years ago
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