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pshichka [43]
3 years ago
12

Find the measure of side b.

Mathematics
1 answer:
malfutka [58]3 years ago
7 0
I think it’s 236.8 correct me if I’m wrong?
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Which of the following are techniques you have learned so far to solve a quadratic equaiton?
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it's d and c

Step-by-step explanation:

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4 years ago
Answer please fast fast fast
dimaraw [331]

Answer:

9 is A 10 is D

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Step-by-step explanation:

9 increases by 4 every time

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5 0
2 years ago
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Mark is a professional race car driver. He has competed in 15 races and won 40% of them. How many races has Mark won?
Law Incorporation [45]

Answer:

6 races

Step-by-step explanation:

If he won 40% of the races he competed in, and he raced 15 times, this means that he won roughly 4/10 races.

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Give brainliest please!

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6 0
2 years ago
Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0
3 years ago
I need the pattern for these numbers,
sergiy2304 [10]
1) 1,8,27,64,95,126,176,230

2)14,16,18,22,24

Hope this helps :)
6 0
3 years ago
Read 2 more answers
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