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Sever21 [200]
2 years ago
5

Which statements about the graph of the function f(x) = –x2 – 4x 2 are true? select three options. the domain is {x|x ≤ –2}. the

range is {y|y ≤ 6}. the function is increasing over the interval (–[infinity] , –2). the function is decreasing over the interval (−4, [infinity]). the function has a positive y-intercept.
Mathematics
1 answer:
dsp732 years ago
8 0

The graph of the function f(x) = –x^2 – 4x +2 are true options 1 and 4 are correct.

We have the given,

The graph of the function f(x) = –x^2 – 4x+ 2

The statements that agree with the graph of the equation are as follows:

1. The domain is {x|x ≤ –2}.

<h3>What is the domain?</h3>

The set of points at which function is defined.

4. The function is decreasing over the interval (−4, ∞).

From the given graph,

We can say that the above statements are true.

To learn more about graphical functions visit:

brainly.com/question/4025726

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Complete the table and then graph the function.<br> y = 5x
sergejj [24]

Answer:

Coordinates: (0,0) ; (1,5) ; (2,10)

Step-by-step explanation:

x  |  y

0  0

1   5

2  10

Coordinates: (0,0) ; (1,5) ; (2,10)

This should be a straight line that is going diagonally with a positive slope.

7 0
2 years ago
What is the measure of
masha68 [24]

Answer:

about 54

Step-by-step explanation:

due to the fact that it is just about a reflection but the thing is that it must be around 90, but it really depends on the angle you measure it at.

6 0
2 years ago
HELP HELP PLEASE!! D:<br> Determine the missing side length!! <br> PLEASE NO CAP!!
charle [14.2K]

Answer:

missing side length = 9

Step-by-step explanation:

c^{2} = a^{2} + b^{2}

a = 6

b = 7

c = missing side

c^{2} = 6^{2} + 7^{2}

c^{2} = 36 + 49

c^{2} = 85

\sqrt{c^{2} } = \sqrt{85}

c = 9.219 = 9

5 0
3 years ago
PLEASE HELP WITH MY MATH!
Marta_Voda [28]
-2^6-(6)^2= -100. Hope this helps have a great day. :)
8 0
3 years ago
Read 2 more answers
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
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