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diamong [38]
3 years ago
9

Indicate the equation of the given line in standard form. The line with slope and containing the midpoint of the segment whose e

ndpoints are (2, -3) and (-6, 5).
Mathematics
1 answer:
Tems11 [23]3 years ago
8 0

Answer:

x + y = -1

Step-by-step explanation:

To write the equation of a line, find the slope and use it with a point in the point slope form.

You can find the slope using the slope formula.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{5--3}{-6-2} = \frac{8}{-8}=-1

Substitute m = -1 and the point (2,-3) into the point slope form.

y - y_1 = m(x-x_1)\\y --3 = -1(x-2)\\y+3=-1(x-2)

Convert to standard form by applying the distributive property and rearranging the terms.

y+3 = -1(x-2)

y + 3 = -x + 2

x + y + 3 = 2

x + y = -1

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V-10=-3 solve the equation
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Answer:

v =7

Step-by-step explanation:

Simplifying

v + -10 = -3

Reorder the terms:

-10 + v = -3

Solving

-10 + v = -3

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + v = -3 + 10

Combine like terms: -10 + 10 = 0

0 + v = -3 + 10

v = -3 + 10

Combine like terms: -3 + 10 = 7

v = 7

Simplifying

v = 7

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\\ \sf\longmapsto x+5+x-5=80

\\ \sf\longmapsto 2x=80

\\ \sf\longmapsto x=40

Angles are

  • 180-80=100°
  • x+5=40+5=45°
  • x-5=40-5=35°

No sean was wrong

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