-8 and -9 because it is negative
The graph described is the graph of a quadratic function.
The x-intercept of the function is at; (8, 0).
<h3>What type of function is described by the graph?</h3>
It follows from the description box of the graph that it begins in the third quadrant, and rises through a series of points in the first quadrant before it exits the first quadrant.
Hence, it follows that the graph is a quadratic function and its x-intercept is at point; (8,0).
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Answer:
7
Step-by-step explanation:
Substitute x = -4 :
f(-4) = 3 - (-4)
= 3 + 4
= 7
Answer:
4y = 6x + 40
Step-by-step explanation:
The general equation of a straight line is y = mx + b
m is the slope and b is the y-intercept
let us write both equations in this form;
we have this as;
6y = -4x + 1
y = -4x/6 + 1/6
and;
2x + 3y = 18
3y = -2x + 18
y = -2x/3 + 6
So firstly we want to find an equation that is perpendicular to the first
When two lines are perpendicular, their slopes has a product of -1
The slope of the first line is -4/6
let the slope of the line we want be m
As per they are perpendicular;
-4/6 * m = -1
-4m/6 = -1
-4m = -6
m = 6/4
So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6
we can choose 10
and we have the equation as:
y = 6x/4 + 10
multiply through by 4
4y = 6x + 40
Answer:
the equation is y = ax + b (a ≠ 0)
see in the graph, the line passed through (0;3) and (1;5)
=>b = 3
a + b = 5
<=> a = 2
b = 3
=> the equation is y = 2x + 3
Step-by-step explanation:
