All categories

2 years ago

If u have 975,158 bananas and u divided 901,928 more bananas how much do u have??

Mathematics

1 answer:

Zarrin [17]2 years ago

3 0

You will have 1,877,086 bananas.

<h3>Quantity calculation</h3>

To determine, if you have 975,158 bananas and you add 901,928 more bananas, how much do you have, the following calculation must be performed:

975,158 + 901,928 = X
1,877,086 = X

Therefore, you will have 1,877,086 bananas.

Learn more about quantity calculation in brainly.com/question/27388041

You might be interested in

6-2x=5x-9x+12 what is the value of x its for savvas realize

Sidana [21]

Answer:like terms: 5x + -9x = -4x 6 + -2x = -12 + -4x Solving 6 + -2x = -12 + -4x Solving for variable 'x'.

Step-by-step explanation:

6 - 2x = 5x - 9x + 18 - 12 6 - 2x = -4x + 6 -2x = -4x 4x - 2x = 0 2x = 0 x = 0 / 2 x = 0.

7 0

2 years ago

Read 2 more answers

If you help me just explain it to me

love history [14]

Answer:

Step-by-step explanation:

lets find median 2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

now lets find the lower quartile median and upper quartile median

we don't include the median in the count, only use it to divide the data into the two parts,

2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

so lower quartile median is 4,

2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

while upper quartile median is 10

the box represents the range between the upper quartile median and lower quartile median, thus is should go from 4 to 10 with the middle line, representing the median at 8,

the whiskers represent the whole data range

thus, the answer is C

6 0

3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Volgvan

Answer:

a) The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

Step-by-step explanation:

Step(i):-

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

Step(ii):-

Null Hypothesis H₀ : μ >10

Alternative Hypothesis : H₁ : μ < 10

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$

t = 5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄ = 2.572

The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

p- value :

p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

8 0

3 years ago

**EZ 35 POINTS**

VLD [36.1K]

Kent can paint the room 1/5
luannda can paint the room 1/3
(3+5) (5*3) = 8/15 or 0.53 th of the room together but just for kent would be 1/5

6 0

3 years ago

What is the quotient (x^3-3x^2+3x-2) divided by (x^2-x+1)

Zielflug [23.3K]

If you do the long division you'll see that it is x - 2.

4 0

3 years ago