The volume (in m3) of water in my (large) bathtub when I pull out the plug is given by f(t)=4−t2 (t is in minutes). This formula
is only valid for the two minutes it takes my bath to drain.
(a) Find the average rate the water leaves my tub between t=1 and t=2
(b) Find the average rate the water leaves my tub between t=1 and t=1.1
(c) What would you guess is the exact rate water leaves my tub at t=1
(d) In this bit h is a very small number. Find the average rate the water leaves my tub between t=1 and t=1+h (simplify as much as possible)
(e)
What do you get if you put in h=0 in the answer to (d)?
1 answer:
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Answer:-7
Step-by-step explanation:
85/5 = 17
12*3=36
4*3=12
17-36+12
-19+12
-7
The distance for robot walks speed is D 20 feet per minute
The answer should be 5 degrees. The temperature starts at 8 degrees and decreased to 3 degrees. Therefore you find the missing addend which in this case is 5 degrees. 8-3=5
If the length is 4 times from DE=4AB then the corresponding length of EF which is BC is also 4 times larger. Length of BC=sqrt((2-1)^2+(-1-3)^2)=sqrt of 17 Hence, length of EF is 1/4 of sqrt 17. Hope it helps
Answer:
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Step-by-step explanation:
