3 years ago

The student council at Baruch is sponsoring a T-shirt sale. They plan to take orders in advance so they

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

Answer:

Step-by-step explanation:

-350-210=-560+200=-360/-14=25.71

You can't have 25.71 T-shirts, so add 1 more to get 26.

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Tyler fills up his tank with 12 gallons of gas. If one trip, on average,takes 1/2 gallon of gas, how many trips will the Tyler b

Bingel [31]

24
Since each trip takes half a gallon of gas, you divide the amount of gas by how much per trip.
That gives you 24 trips he can make with the gas.

7 0

3 years ago

5h+4+52+64=180 what does that equal to

Softa [21]

Answer:

x=12

Step-by-step explanation:

5x+4+64+52=180

We move all terms to the left:

5x+4+64+52-(180)=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

8 0

3 years ago

Ed intends to roll a six-sided number cube 100 times. What probability model can he use to predict whether or not each roll will

Stells [14]

The answer is Each roll has a 0.333 probability of being composite.

<em>(I just took the test, B was the answer)</em>

8 0

2 years ago

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Amelia stores her gardening supplies in two cube shaped boxes. The smaller box has a volume of 100 inches to the third power. Am

Solnce55 [7]

Answer:

1000000 for the smaller box.

I need more info for the second box

Step-by-step explanation:

6 0

2 years ago

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Jia is skipping a rock across a pond. The sequence {4.2, 3.57, 3.0345, 2.5793, …} describes the height of the rock on each succe

mylen [45]

Answer:

$u_n=4.2(0.85)^{n-1}$

Step-by-step explanation:

$u_1=4.2\\u_2=3.57\\u_3=3.0345\\u_4=2.5793$

Geometric formula sequence: $u_n=ar^{(n-1)}$

(where $a$ is the first term of the sequence and $r$ is the common ratio)

To find the common ratio, divide one of the terms by the previous term:

$r=\frac{u_2}{u_1} =\frac{3.57}{4.2} =0.85$

From inspection, $a=4.2$

Therefore, $u_n=4.2(0.85)^{n-1}$

8 0

1 year ago

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