Step-by-step explanation:
We have, Sorin hits a cricket ball straight up into the air. After 1.5 s, the ball is falling straight down with a speed of 6.5 m/s.
We want to find the initial vertical velocity of the ball.
The relation between initial speed, final speed, acceleration and time is given by using first equation of kinematics. Let v₀ is the initial speed. So,

Here, v = -6.5 m/s, t = 1.5 s and a = -g

So, the initial velocity of the ball is 8.2 m/s and the formula used is (1).
Answer:
sqrt (90)
Step-by-step explanation:
(13+5) is to z as z is to 5
(13+5) / z = z/5
18/z = z/5
90 = z^2
z = sqrt (90)
If you want to evaluate it, -4q-(-8q)+10 is changed to -4q+8q+10 (two negatives equal positive). Next, -4q+8q is 4q (since the bigger number is positive 8q, you subtract and get 4q). Finally, your answer is 4q+10. Hope this helps! :)