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Nana76 [90]
3 years ago
5

Convert this identity to one using sine term(s) only. 1-2cos(r)^2

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
Pythagorean identity:
sin²+cos²=1
Then cos²=1-sin²
Substitute:
1-2cos²
1-2(1-sin²)
1-2+2sin²
2sin²-1
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How do this problem?
Naily [24]
1/5(3x - 0.5) + 1/6= x/5 + 0.5
change decimals to fractions (0.5=1/2)

1/5(3x - 1/2) + 1/6= x/5 + 1/2
multiply 1/5 by each term in parentheses

(1/5*3x) + (1/5*-1/2) + 1/6= x/5 + 1/2
multiply within parentheses

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need a common denominator; all denominators go into 30

18x/30 - 3/30 + 5/30= 6x/30 + 15/30
combine like terms

18x/30 + 2/30= 6x/30 + 15/30
subtract 6x/30 from both sides

12x/30 + 2/30= 15/30
subtract 2/30 from both sides

12x/30= 13/30
multiply both sides by 30 to eliminate fractions

(12x/30)(30)= (13/30)(30)
12x= 13
divide both sides by 12

x= 13/12 or 1.083333


ANSWER: x= 13/12 or 1.083333

Hope this helps! :)
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What is the probability of rolling a sum of 5 on a standard pair of six-sided dice? express your answer as a fraction or a decim
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The probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.

According to the given question.

A standard pair of dice is rolled.

So, the sample sapce for rolling a pair of dice = {(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4),(5, 5),(5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

⇒ Total number of outcomes = 36

And, the outcomes for getting a sum of five on a sandard pair of six sided dice = {(2, 3), (3, 2), (4, 1), (1, 4)}

⇒ Total number of favorable outcomes = 4

As we know that " probability is the ratio of total number of favorable outcomes to the total number of outcomes".

Therefore,

The probability of rolling a sum of 5 on a standard pair of six-sided dice

= 4/36

= 1/9

Hence, the probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.

Find out more information about probability here:

brainly.com/question/11234923

#SPJ4

8 0
2 years ago
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