Question

During, an Experiment, The temperature of a solution changes from 9 4/5 F to 17 1/4 F.

Answer 1

Using improper fractions, it is found that the percent of increase in the temperature of the solution was of 76.08%.

How to convert improper fractions to standard fractions?

The conversion is made according to the following formula:

$a\frac{b}{c} = a + \frac{b}{c} = \frac{ac + b}{c}$

In this problem, the initial temperature was given by:

$9\frac{4}{5} = 9 + \frac{4}{5} = 9.8$

The final temperature was given by:

$17\frac{1}{4} = 17 + \frac{1}{4} = 17.25$

What is the percent change?

The percent change is given by the change divided by the initial temperature, and multiplied by 100%. Hence:

$C = \frac{17.25 - 9.8}{9.8} \times 100\% = 76.02\%$

To learn more about improper fractions, you can take a look at brainly.com/question/24606703