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maks197457 [2]
2 years ago
10

During, an Experiment, The temperature of a solution changes from 9 4/5 F to 17 1/4 F.

Mathematics
1 answer:
cupoosta [38]2 years ago
4 0

Using improper fractions, it is found that the percent of increase in the temperature of the solution was of 76.08%.

<h3>How to convert improper fractions to standard fractions?</h3>

The conversion is made according to the following formula:

a\frac{b}{c} = a + \frac{b}{c} = \frac{ac + b}{c}

In this problem, the initial temperature was given by:

9\frac{4}{5} = 9 + \frac{4}{5} = 9.8

The final temperature was given by:

17\frac{1}{4} = 17 + \frac{1}{4} = 17.25

<h3>What is the percent change?</h3>

The percent change is given by the change divided by the initial temperature, and multiplied by 100%. Hence:

C = \frac{17.25 - 9.8}{9.8} \times 100\% = 76.02\%

To learn more about improper fractions, you can take a look at brainly.com/question/24606703

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