(64 / 8 + 2 - 10) + (9 x 9 + 19) = 2 points 100 90 99

Rainbow [258]

For the first option, the range is a measure of variability which measures the spread of the data set from the least value to the greatest value, but it does not take into account the variability of the other data values of the data set. The range is easily affected by the presence of outliers (data points that are away from other data points). Thus the range is regarded as a weak measure of variability and is not used when other measures of variability are available. Thus, that the range of the two data sets are equal does not mean that the data sets have the same variability. Therefore, the first option is not the correct answer.

For the second option, the median is not a measure of variability. Thus, that a data set has a greater median than another data set does not mean that the data set would have a greater variability. Therefore, the second option is not the correct answer.
For the third option, the inter-quartile range (IQR) is a better measure of variability than the range because it takes into account more data points than the range. Now, because, the the IQR of Team 2 is less than the IQR of Team 1, this shows that Team 1 have greater variability than Team 2 and thus the conclusion of the coaches are inaccurate. Therefore, the third option is the correct answer.

For the fourth option, the mean absolute deviation, MAD, is a better measure of variability than the IQR because it takes into account all the points of the data set. While IQR measures variability with respect to the median, MAD measures variability with respect to the mean. Because we are told that the data sets are not symmetrical, the median will be a better measure of the center than the mean, thus the IQR will present a better measure of the variability of the data sets. Thus, though the MAD for Team 2 was calculated to be a larger number than the MAD for Team 1, the information can be misleading in arriving at a conclusion on which data set has more variability because the data sets are not symmetrical. Therefore, the fourth option is not the correct answer.

4 0

3 years ago

Read 2 more answers

Answer all for points

IceJOKER [234]

Answer:

1. If we drink 8 glasses, we are drinking 2 L of water, so we are exceeding 1 L of water per day.

2. We need 100 sections.

I used metric conversion to convert km to meters.

3. 230 mL of lemonade per person

I used metric conversion to convert L to ML

Step-by-step explanation:

1. 250 mL = 1 glass

We are drinking 8 glasses

8 glasses * 250 ml/ 1 glass = 2000 mL

1 L = 1000 mL

2000 mL * 1 L/1000 mL =2 L

If we drink 8 glasses, we are drinking 2 L of water, so we are exceeding 1 L of water per day.

I used metric convertsion to convert mL to liters.

Guardrails sections to be 5m long

Road length that needs a guardrail is .5 km. We need to convert this to meters 1000 m = 1 km

.5km * 1000m / 1km = 500 meters

We have 500 meters that needs guardrails.

500 meters * 1 section/ 5 meters = 100 sections

We need 100 sections.

I used metric conversion to convert km to meters.

3. 6.9 L of lemonade to serve 30 people. We want to serve ml

Convert L to mL

1L = 1000 ML

6.9 L * 1000 ml/1L = 6900 mL

We need to divide 6900 Ml by 30 people

6900mL/30 people = 230 mL of lemonade per person

I used metric conversion to convert L to ML

5 0

3 years ago

Hello can you please help posted picture of question

lesya692 [45]

We know that

the graphic has two intervals
x>1------> (1,∞)
equation of second order
and
x<=1------> (-∞, 1]
equation of a line

therefore
<span>The only option that meets these requirements is option A
</span>
the answer is
the option A

3 0

3 years ago

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) = speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s