The correct answer would be A
Child corona hit when i was trying to "learn" that
Answer:2
Step-by-step explanation: cot2θ+cosec2θ
=![\frac{cot^{2}\theta }{2cot\theta} +\frac{1}{sin^{2}\theta }](https://tex.z-dn.net/?f=%5Cfrac%7Bcot%5E%7B2%7D%5Ctheta%20%7D%7B2cot%5Ctheta%7D%20%2B%5Cfrac%7B1%7D%7Bsin%5E%7B2%7D%5Ctheta%20%7D)
=![\frac{2^{2}-1 }{2*2} \\](https://tex.z-dn.net/?f=%5Cfrac%7B2%5E%7B2%7D-1%20%7D%7B2%2A2%7D%20%5C%5C)
/1+cot²θ
=![\frac{4-1}{4} +\frac{1+2^{2} }{2*2}](https://tex.z-dn.net/?f=%5Cfrac%7B4-1%7D%7B4%7D%20%2B%5Cfrac%7B1%2B2%5E%7B2%7D%20%7D%7B2%2A2%7D)
=![\frac{3}{4} +\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2B%5Cfrac%7B5%7D%7B4%7D)
=![\frac{8}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B4%7D)
=![2](https://tex.z-dn.net/?f=2)
The equation of the line will be y = ![\dfrac{1}{5}x + \dfrac{12}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B5%7Dx%20%2B%20%5Cdfrac%7B12%7D%7B5%7D)
<h3>What is an equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
First, we need to find the equation of the line that is given:
We can use the formula,
![m=\dfrac{-3-(-4)}{0-(-5)}=\dfrac{1}{5}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-3-%28-4%29%7D%7B0-%28-5%29%7D%3D%5Cdfrac%7B1%7D%7B5%7D)
So the equation for this line is
y = (1/5) x - 3
This means that the equation for the line we are trying to find has a slope of as well
Let's put the points in the equation and try to find the y-intercept:
2 =
( -2 ) + b
![\dfrac{15}{5} = b](https://tex.z-dn.net/?f=%5Cdfrac%7B15%7D%7B5%7D%20%3D%20b)
So the final equation for the line we are trying to find is y = ![\dfrac{1}{5}x + \dfrac{12}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B5%7Dx%20%2B%20%5Cdfrac%7B12%7D%7B5%7D)
To know more about equations follow
brainly.com/question/2972832
#SPJ1
Answer:
1. ![(f^{-1}og^{-1}) (x) = \sqrt{x^{2}+3 }](https://tex.z-dn.net/?f=%28f%5E%7B-1%7Dog%5E%7B-1%7D%29%20%28x%29%20%3D%20%5Csqrt%7Bx%5E%7B2%7D%2B3%20%7D)
2. ![(f o g)^{-1} (x) = x + 3](https://tex.z-dn.net/?f=%28f%20o%20g%29%5E%7B-1%7D%20%28x%29%20%3D%20x%20%2B%203)
Step-by-step explanation:
f(x) =
+ 1
putting f (x) = y
y =
+ 1
= ( y-1)
x = ![(y - 1)^{\frac{1}{2} }](https://tex.z-dn.net/?f=%28y%20-%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
Therefore =
= ![(x-1)^{\frac{1}{2} }](https://tex.z-dn.net/?f=%28x-1%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
g (x) = ![\sqrt{x-4}](https://tex.z-dn.net/?f=%5Csqrt%7Bx-4%7D)
putting g(x) = y
y = ![\sqrt{x-4}](https://tex.z-dn.net/?f=%5Csqrt%7Bx-4%7D)
= (x-4)
x = ![y^{2} + 4](https://tex.z-dn.net/?f=y%5E%7B2%7D%20%2B%204)
![g^{-1} (x) = x^{2} + 4](https://tex.z-dn.net/?f=g%5E%7B-1%7D%20%28x%29%20%3D%20x%5E%7B2%7D%20%2B%204)
(
o ![g^{-1}) x](https://tex.z-dn.net/?f=g%5E%7B-1%7D%29%20x)
![(g^{-1}x -1)^{\frac{1}{2} } = \sqrt{x^{2} +3}](https://tex.z-dn.net/?f=%28g%5E%7B-1%7Dx%20-1%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%3D%20%5Csqrt%7Bx%5E%7B2%7D%20%2B3%7D)
2. (f o g)(x) = (√x-4)²+1) = x-4+1
(f o g)(x) = x-3
Let y = x - 3
x = y + 3
Or ![(f o g)^{-1}(x) = x + 3](https://tex.z-dn.net/?f=%28f%20o%20g%29%5E%7B-1%7D%28x%29%20%3D%20x%20%2B%203)