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Ratling [72]
3 years ago
9

Solve the equation -6 + 3x = -9

Mathematics
2 answers:
sammy [17]3 years ago
3 0

First you had to add by six from both sides of equation form.

-6+3x+6=-9+6

Then simplify.

3x=-3

Next you divide by three from both sides of equation form.

\frac{3x}{3}= \frac{-3}{3}

Finally simplify by equation.

\frac{-3}{3}=-1

x=-1

Final answer \boxed{x=-1}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

galina1969 [7]3 years ago
3 0

Hey there!!

We have:

... -6+3x=-9

What is the value of 'x' so that it fits the scenario.

<em>If we fit the value of 'x'in the given equation, then, we will have to get -9. </em>

... -6+3x=-9

Now, let's add 6 on both sides so we could get all the variables on one side and the constants on one side.

<em>This would make it easier for us to find out the value x. </em>

... -6 + 3x + 6 = -9 + 6

... 3x = -3

Now, let's divide 3 on both sides to isolate the x.

... 3x / 3 = -3/3

... x = -1.

<em>Hence, the value of x is -1 . </em>

Hope my answer helps!

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soldi70 [24.7K]

Answer:

Relative\ Frequency = 0.04

Step-by-step explanation:

Given

Cost of Textbooks ---- Frequency

$25 up to $35  -----      2

$35 up to $45 -------     5

$45 up to $55  -------    7

$55 up to $65   ------    20

$65 up to $75   ----   -- 16

Required

Determine the relative class frequency for the $25 up to $35 class

First, we need to get the total frequency

Total = 2 + 5 + 7 + 20 + 16

Total = 50

Next, is to write out the frequency of $25 up to $35 class

Frequency = 2

Divide this frequency by the total frequency; This gives the relative frequency

Relative\ Frequency = \frac{Frequency}{Total}

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Relative\ Frequency = 0.04

Hence;

Option D answers the question

4 0
3 years ago
Need help 6th grade math
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Answer:

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Step-by-step explanation:

4 0
2 years ago
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Step-by-step explanation:

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The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

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Where r is the radius and

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As per question statement:

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\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

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4 0
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