Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
<h3>How to determine how many bead of each type of bracelets and necklaces should Christy make to maximize his profit?</h3>
The given parameters can be represented in the following tabular form:
Bracelet (x) Necklace (y) Total
Labor (hour) 0.5 0.75 40
Profit 10 18
From the above table, we have the following:
Objective function:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
Because she wants to make at least 30 bracelets, we have:
x >= 30
So, we have:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
x >= 30
Express x >= 30 as equation
x = 30
Substitute x = 30 in 0.5x + 0.75y <= 40
0.5 * 30 + 0.75y <= 40
This gives
15 + 0.75y <= 40
Subtract 15 from both sides
0.75y <= 30
Divide by 0.75
y <= 40
Hence, Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
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Answer:
Farthest left 1 1/3
Step-by-step explanation:
5-4 = 1
Since the denominators are the same, subtract 2 and 1
Step-by-step explanation:
D=9
A=pie*radius^2
=3.14*9/2*9/2
=63.58
=64
You first must find the 18% of the fish population.
You multiply 500 by .18 . You are supposed to get 90.
90 is the 18% fish increase.
Then you just add 500 + 90 and you will get 590 fish that are now in the school.
Answer:
B)x=23
y=20
Step-by-step explanation:
