Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,
which is a cubic polynomial in 
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,
where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then 
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
Answer:
1 minute and 8 seconds or 1:08
Step-by-step explanation:
by subtracting both at starting with 9:17-8:49 you will get a uneven decimal than you gonna have to give as much 60 seconds you can get out of it the 60 seconds equals a minute
Answer:
(7, 0) and (3,0)
Step-by-step explanation:
On the graph, the parabola crosses the x-axis at two points. The two points are called the roots. And since they cross at (7, 0) and (3, 0), they are our roots. Hope this helps!
8x + 7y = 19
- 8x
7y = 19 - 8x
÷ 7
y = 2 5/7 - 8/7x
So if that line is perpendicular to the line you're looking for, then the gradient (x value/slope) is the negative reciprocal to the gradient you're looking for, which would then be 7/8. You are told it has a y intercept of -7, so your final answer is:
y = -7/8x - 7
Hope this helps!
make a line going straight from (0,0) to (2,2) and so on and the other line starts at (0,0) and go to (1,1) and follow along the other line
