

Consequently, t<span>he limit of

as x approaches infinity is

.
In other words,

approaches the line y=x,
</span><span>
so oblique asymptote is y=x.
I'm Japanese, if you find some mistakes in my English, please let me know.</span>
Y=1x+2 (you don’t have to write the 1 in front of the x so you can write it as y=x+1)
X cannot equal +2, and can't be -1. If you factor it, then you notice you get 2(x+2)(x-2). If you use either one for the x, one will be zero and the won't, and vise-versa.
Answer:
It is 2πrh + 2π
Step-by-step explanation: