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Citrus2011 [14]
3 years ago
9

Thomas lives 350 miles from the beach. He drives to the beach at an average rate of 50 miles per hour. Use that information and

the diagram to complete the table below.

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

Step-by-step explanation:

use the equation: y =50x-350 where x is the number of hours driving

hrs                

1      50            300

2      100          250

3       150          200

5       250         100

7        350           0

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Write an equation in slope-intercept form (0,2) (7,-1)
maksim [4K]

Answer:

y=-3/7x+2

Step-by-step explanation:

first formula (Slope): y2-y1/x2-x1

-1-2/7-0= -3/7

second formula (point slope): y-y1=m(x-x1)

y-2=-3/7(x-0)

(distribute the -3/7)

y-2=-3/7x-0

(add 2 to both sides)

y=-3/7x+2

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3 years ago
Hello fellow Brainliers. I was wondering if anyone out there would like to go to school for me during the next school year and a
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Answer:

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3 years ago
How many solutions can be found for the equation 4z 2(z − 4) = 3z 11? none one two infinitely many
Rus_ich [418]

There is only one solution for the equation 4z + 2(z -4) = 3z + 11 because the exponent for the power of z is 1.

<h3>What is an equation?</h3>

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

<h3>What is the Solution?</h3>

A solution is any value of a variable that makes the specified equation true.

According to the given information:

4z + 2(z-4)= 3z+11

Solve the equation,

4z+2z-8=3z+11

6z-3z=11+8

3z =19

z=

Hence,

Number of solution that can be found for the equation 4z + 2(z-4)= 3z+11 is option(2) one

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8 0
2 years ago
What is the domain and range of the graph?
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Answer:5/8

Step-by-step explanation:

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3 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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