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2 years ago

Please help with a picture

Mathematics

2 answers:

AlexFokin [52]2 years ago

5 0

Answer:

plzz give me brainlist

Step-by-step explanation:

Download docx

Leni [432]2 years ago

3 0

Answer:

Step 1: Copy a segment and an angle.

Which step in the construction of copying a line segment ensures that the new line segment has the same length as the original line segment?

Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long as .

The construction of copying is started below. The next step is to set the width of the compass to the length of . How does this step ensure that the new angle will be congruent to the original angle?

How is copying a line segment similar to copying an angle?

Step 2: Construct a perpendicular line.

In the step shown of the construction of a line through a point that is perpendicular to the given line, why must the compass point be placed on points A and B? How would the construction be different if the compass point were placed at random points on the original line?

Step 3: Construct an angle and a perpendicular bisector.

The construction of creating the perpendicular bisector of is started below. How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?

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Plss help! Question: Find a,b and c

Roman55 [17]

Answer:

See below, please

Step-by-step explanation:

The right：

${(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba =$

$= {y}^{2} - bx + 2cy + {c}^{2} - ab$

The left:

$= {y}^{2} - 7x - 18y + 109$

So, after comparing the right side and the left side of this equation, we know

$b = 7$

$2c = - 18 \\ so \\ c = - 9$

${c}^{2} - ab = 109$

So,

$a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4$

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2 years ago

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3 years ago

In the year 1995, there were 1200 students at pine elementary school. In the year 2010 there were 1500 students. Find the rate o

AnnZ [28]

The rate of change from 1995 to 2010 is 20 students per year and the linear function that models the data will be: $y=20x-38700$

Explanation

In the year 1995, there were 1200 students and in the year 2010, there were 1500 students.

If $x$ represents the year and $y$ represents the number of students, then two points in form of $(x,y)$ will be: $(1995, 1200)$ and $(2010, 1500)$

So, the rate of change or slope = (change in value of y / change in value of x) $=\frac{1500-1200}{2010-1995}= \frac{300}{15}=20$

Now, plugging slope $(m)$ = 20 and first point $(x_{1}, y_{1}) =(1995,1200)$ into point slope form of linear equation $y-y_{1} =m(x-x_{1})$ , we will get.....

$y-1200=20(x-1995)\\ \\ y-1200=20x-39900\\ \\ y= 20x-39900+1200\\ \\ y= 20x-38700$

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