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2 years ago

Be sure yo write 3-4 sentences.

Mathematics

1 answer:

Anit [1.1K]2 years ago

3 0

Answer:

top area = 10.125

Step-by-step explanation:

Formulas used

triangle: base × height / 2

rectangle: base × height

1.5×1.5=2.25

2.25 / 2 = triangle = 1.125

1.5×3=4.5

4.5 × 2 because we have two of the same rectangles.

4.5×2 = both rectangles = 9

add our triangle and rectangles gives our top.

9+1.125 = top = 10.125

explained in sentences:

I found the base and height of my formulas. then used a calculator to help me solve. Which got me the answer of 10.125 when I added area of two rectangles and one triangle.

You might be interested in

In the number 38. 7165, what number is in the hundredths position?

Sati [7]

Answer:

Step-by-step explanation:

Your answer is 1 because hundredths position is the second number after the decimal other answers include.

Ten=3

Ones place=8

Tenths place=7

Thousandths place=6

Hundred thousandths=5

Hope it helps have a great day:)

4 0

2 years ago

We have 9 cards numbered 1 to 9. Two cards are drawn at random. What is the probability that the sum of the drawn cards is a pri

emmainna [20.7K]

There are 5 cards less than nine that are prime, so there is a 5/9 chance of picking the first one prime. The second one would be 4/8 or 1/2, because you have removed a card from the deck. You multiply them together to get: 5/18.

Hope this helps!

6 0

3 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

What is greater than 40 but less than 20

Paladinen [302]

I've already been complemented twice on my previous answer, but then I discovered that I mis-read the question. My entire original answer was wrong, and I have to delete it.

I don't believe that any number can satisfy both of those conditions.
I'll say the question has no answer.

3 0

3 years ago

can someone please help with my geometry homework?? i haven't been in the class for a year and i'm starting off the second semes

sattari [20]

Ok so for number 5, AB is proportional to BC just like PQ is proportional to QR. AB = 9, BC = 15, PQ = 3, and QR = x. 9/15 = 3/x. Cross Multiply: This gives you - 9x = 45. Divide both sides by 9, and you get x = 5. QR = 5

3 0

3 years ago