Answer: False
Explanation:Low-end CRM system are specifically designed for those companies which are small scale but can connect to many businesses or organization at a time. These are the customer relationship management system that happens to analyze the functioning of the business with high count of small companies with appropriate amount of customers.Thus, the statement given is false.
Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
Answer:
The British inventor Fox Talbot produced his first successful photographic images in 1834, without a camera, by placing objects onto paper brushed with light-sensitive silver chloride, which he then exposed to sunlight.
Explanation:
Answer:
The program in C++ is as follows:
#include <iostream>
using namespace std;
int perimeter(int side1, int side2, int side3){
return side1+side2+side3;
}
struct Triangle {
int side1; int side2; int side3;
};
int main(void) {
int side1, side2, side3;
cout<<"Sides of the triangle: ";
cin>>side1>>side2>>side3;
struct Triangle T;
T.side1 = side1;
T.side2 = side2;
T.side3 = side3;
cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;
return 0;
}
Explanation:
See attachment for complete code where comments are as explanation
Answer:
#include <iostream>
#include<iomanip>
using namespace std;
double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)
{
double dollarCost = 0;
dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;
return dollarCost;
}
int main()
{
double miles = 0;
double dollars = 0;
cout << "Enter miles per Gallon : ";
cin >> miles;
cout << "Enter dollars per Gallon: ";
cin >> dollars;
cout << fixed << setprecision(2);
cout << endl;
cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;
cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;
cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;
return 0;
}
Explanation:
- Create a method definition of DrivingCost that accepts three input double data type parameters drivenMiles, milesPerGallon, and dollarsPerGallon and returns the dollar cost to drive those miles
.
- Calculate total dollar cost and store in the variable, dollarCost
.
- Prompt and read the miles and dollars per gallon as input from the user
.
- Call the DrivingCost function three times for the output to the gas cost for 10 miles, 50 miles, and 400 miles.
