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1 year ago

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A Zoo Has a Elephant to giraffe ratio of 1 to 5. There are 18 Total animals. How many are giraffes? (Please Answer Quickly i rea

lly need this!!!)

1 answer:

Julli [10]1 year ago

5 0

There are 15 giraffes in the zoo.

Let the Elephant be E.

Let the Giraffe be G.

<u>Given the following data:</u>

Total animals = 18 animals

Ratio of E to G = 1:5

Total ratio= 1 + 5 = 6

To find how many of the animals are giraffes:

$G = \frac{Ratio \; of \; giraffe}{Total \; ratio}$ × $Total \; animals$

Substituting the values, we have;

$G = \frac{5}{6}$ × $18$

$G = \frac{90}{6}$

<em>Giraffe, G </em><em>=</em><em> 15 giraffes</em>

Therefore, there are 15 giraffes in the zoo.

Ratio: brainly.com/question/12212308

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In a pre algebra class containing 40 students, there are 18 freshmen, 19 sophomores, and 3 juniors. What fraction of the class a

dezoksy [38]

$\frac{9}{20}$ of the class consists of freshmen.

Step-by-step explanation:

Given,

Total number of students = 40

Number of freshmen = 18

Number of sophomores = 19

Number of juniors = 3

Fraction of freshmen = $\frac{Number\ of\ freshmen}{Total\ number\ of students}$

Fraction of freshmen = $\frac{18}{40}$

Fraction of freshmen = $\frac{9}{20}$

$\frac{9}{20}$ of the class consists of freshmen.

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3 years ago

The value of a machine depreciates each year by 5% of its value at the beginning of that year.If its value when new on 1st Janua

luda_lava [24]

Answer:

6460 pounds approx.

Step-by-step explanation:

Depreciation = P( 1 - r/100)^n [ n = time period, P= Principal and r= rate}

= 10,250(1-5/100)^9

= Approx. 6460 pounds

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2 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

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3 years ago

Can someone help me with these two problems and show work please !!

irina1246 [14]

Work is attached to this post

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1 year ago

Read 2 more answers

Solve 3-(2x-5)<-4(x+2)

azamat

Answer:

Step-by-step explanation:

3-(2x-5)=-4(x+2)

We simplify the equation to the form, which is simple to understand

3-(2x-5)=-4(x+2)

Remove unnecessary parentheses

3-2x+5=-4*(x+2)

Reorder the terms in parentheses

3-2x+5=+(-4x-8)

Remove unnecessary parentheses

+3-2x+5=-4x-8

We move all terms containing x to the left and all other terms to the right.

-2x+4x=-8-3-5

We simplify left and right side of the equation.

+2x=-16

We divide both sides of the equation by 2 to get x.

x=-8

7 0

2 years ago

Read 2 more answers