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3 years ago

Given Q below, is YQR a minor arc, a major arc, or a semicircle?

Mathematics

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

B. Major arc.

Step-by-step explanation:

We have been given diagram of circle Q. We are asked to determine whether YQR is a minor arc, a major arc, or a semicircle.

Upon looking at our given circle, we can see that major of arc RY is 150 degrees.

We also know that major of all arcs is a circle is equal to 360 degrees. So we can set an equation as:

$\widehat{YQR}+\widehat{RY}=360^{\circ}$

Upon substituting measure of arc RY, we will get:

$\widehat{YQR}+150^{\circ}=360^{\circ}$

$\widehat{YQR}+150^{\circ}-150^{\circ}=360^{\circ}-150^{\circ}$

$\widehat{YQR}=210^{\circ}$

Since measure of arc is YQR is greater than 180 degree, therefore, arc YQR is a major arc.

zmey [24]3 years ago

6 0

Major arc, because it's bigger than a semicircle

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What is the volume of a right circular cone if the circumference of the base is 125.6 ft and the height is 75 ft.?

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Answer:

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Step-by-step explanation:

We must first need to understand how the volume of a cone is calculated.

It is simply calculated by multiplying the base area of the cone by the height, and dividing the result by 3.

This is :

Volume of cone = $\frac{\pi r^2 h}{3}$

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3 years ago

Read 2 more answers

The sales decay for a product is given by S = 70000e^ -0.8x where S is the monthly sales and x is the number of months that have

Gre4nikov [31]

Answer:

After 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09

Step-by-step explanation:

Let's find the solutions for the two questions.

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Because the problem asks for how many months, and since 'x' represents month variable, then the problem is asking for 'x'.

Using the same equation for sales we can observe the following:

$S=70000*e^{-0.8X}$ , but we have S which is 1000, so:

$1000=70000*e^{-0.8X}$ which is equal to:

$1000/70000=e^{-0.8X}$ which is equal to:

$1/70=e^{-0.8X}$ by applying ln(x) properties:

$ln(1/70)=ln(e^{-0.8X})$ which is equal to:

$ln(1/70)=-0.8X$ which is equal to:

$ln(1/70)/(-0.8)=X$ so:

$X=5.31 months$

Second question: what will be the sales 5 months after the end of the campaign.

Because the problem asks for what will be the sales, and since 'S' represents the sales, then the problem is asking for 'S'.

Using the same equation for sales we can observe the following:

$S=70000*e^{-0.8X}$ , but we have x which is 5 months, so:

$S=70000*e^{-0.8*5}$ which is equal to

$S=1282.09$

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