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2 years ago

PLESE HELP!! im teribul at these!!

Mathematics

2 answers:

marshall27 [118]2 years ago

4 0

The y-intercept is "equal to", "y=1", "x=0".

_____
The y-intercept is the "+1" part of the equation y=2x+1.

aleksandr82 [10.1K]2 years ago

4 0

Answer: equal too

hope this helps

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

3 years ago

Not hard <br> 2x−4y=14<br> 3y+5x=9

Vinil7 [7]

Answer:

<h3>HLO,,,WE HAVE TO SIMPLIFY OR WE HAVE TO FIND VALUES</h3>

3 0

2 years ago

I'M GIVING BRAINLIEST

Karolina [17]

I don’t get want u need help with.

4 0

3 years ago

Which expression represents the phrase 12 more than a number times 16

Mars2501 [29]

12+16x is the expression

8 0

3 years ago

Read 2 more answers

the number of buckets of paint n needed to paint a wall varies jointly with the total area a and the thickness t of the wall, an

Nat2105 [25]

The number of buckets is directly proportional to the area and the thickness of the wall and inversely proportional to the amount of paint. Mathematically, we can write:

n = k · (a · t) / p

where k is the proportionality constant which we do not know.

We can calculate k with the given data: 5 2-gallon buckets, area of 100 square feet and thickness 3 inches:

k = (n · p) / (<span>a · t)
   = (5 </span>· 2) / (100 · 3) = 0.0333

Now that we know the constant, we can calculate the area that can be painted with 8 2-gallon buckets if the thickness is 6 inches:

a = (n · p) / (k<span> · t)
   = (8 </span>· 2) / (0.0333 · 6)
   = 80 ft²

Please, note that we made sure to have the exact same units of measurements than the previous case.

Therefore, the correct answer is an area of 80 ft².

4 0

2 years ago