Question

A regular decagon has a radius of 8 cm. what is the approximate area of the decagon? recall that a decagon is a polygon with 10 sides.

Answer 1

The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².

The side of the regular decagon = 8cm

What is a regular decagon?

A regular decagon is a polygon with 10 sides that are equal to each other.

The area of a regular decagon with side a is:

$A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }$

So, the area A of the regular decagon with a side of 8cm:

$A=\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }$

$A=160\sqrt{5+2\sqrt{5} }$

A=492.40 cm²

Therefore, the approximate area of the decagon is 492.40 cm².

To get more about the decagon visit:

brainly.com/question/19899848