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Klio2033 [76]
2 years ago
7

A regular decagon has a radius of 8 cm. what is the approximate area of the decagon? recall that a decagon is a polygon with 10

sides.
Mathematics
1 answer:
lianna [129]2 years ago
7 0

The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².

The side of the regular decagon = 8cm

<h3>What is a regular decagon?</h3>

A regular decagon is a polygon with 10 sides that are equal to each other.

The area of a regular decagon with side a is:

A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }

So, the area A of the regular decagon with a side of 8cm:

A=\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }

A=160\sqrt{5+2\sqrt{5} }

A=492.40 cm²

Therefore, the approximate area of the decagon is 492.40 cm².

To get more about the decagon visit:

brainly.com/question/19899848

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The answer is c. \frac{46}{9}

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