1 of 121 of 12 Items

Wiat number should be added to both sides of the equation to complete the square? X^2+x=11

Ivahew [28]

Answer:

add 1/4 to each side

Step-by-step explanation:

x^2+x=11

We take the coefficient of the x term

1

Then divide it by 2

1/2

Then square it

(1/2) ^2 = 1/4

Add this to both sides of the equation

x^2 + x + 1/4 = 11+1/4

(x+1/2)^2 = 11 1/4

7 0

3 years ago

Read 2 more answers

At a local high school, the probability that a student has a job and a car is 0.18. Jackson wants to find the probability that a

makvit [3.9K]

<span>D. the probability that a student has a car or job

</span>

3 0

3 years ago

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You place a cup of 200oF coffee on a table in a room that is 67oF, and 10 minutes later, it is 195oF. Approximately how long wil

Nikolay [14]

30 minutes i think is the answer?

8 0

3 years ago

Help please I’m stuck

Jlenok [28]

12:4=3
9:3=3
so u multiply each side by 3 to get the second triangle..
answer: 4.5*3 =13.5

4 0

3 years ago

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In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use

seropon [69]

Answer:

Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

$p_v =P(Z>7.36)=9.19x10^{-14}$

Since the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

$\hat p=\frac{492}{778}=0.632$ estimated proportion of people that chose a window seat.

$p_o=0.5$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:

Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>7.36)=9.19x10^{-14}$

5) Conclusion

Since the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .

6 0

3 years ago