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Mandarinka [93]
3 years ago
5

There are 4 second-grade classrooms that share 15 packs of paper. How much paper should each classroom get

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

3.75

Step-by-step explanation:

You might be interested in
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested.1 The seller announced that t
Usimov [2.4K]

Answer:

0.4

Step-by-step explanation:

Given:-

- The uniform distribution parameters are as follows:

                      a = $10,000       b = $15,000

Find:-

Suppose you bid $12,000. What is the probability that your bid will be accepted?

Solution:-

- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].

                                 X ~ U(10,000 , 15,000)

- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:

                                Pmf = 1 / ( b - a )

                                Pmf = 1 / ( 15,000 - 10,000 )

                                Pmf = 1 / ( 5,000 )

                                cdf = \int\limits^x_a {\frac{1}{5000} } \, dy \\\\cdf =  {\frac{y}{5000} }\limits^x_a \\\\P(X

6 0
3 years ago
I need help with the answer.
ivolga24 [154]

Answer:

23

Step-by-step explanation:

5x6-c

5x6=30

30-c

c=7

30-7=23

5 0
4 years ago
Read 2 more answers
What is the value of x? 6x−1=4x−5
ch4aika [34]
X=-2
Explanation is I just know the answer
8 0
3 years ago
Read 2 more answers
2x -3y =2<br><br> x = 6y - 5
never [62]
2(6y - 5) - 3y = 2
12y - 10 - 3y = 2
9y - 10 = 2
9y = 12
y = 4/3, or 1 1/3
2x - 3(4/3) = 2
2x - 12/3 = 2
2x - 4 = 2
2x = 6
x = 3

7 0
3 years ago
The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

  • Minimum: 24.
  • Lower quartile: 29.
  • Median: 43.
  • Upper quartile: 50.
  • Maximum: 56.
  • Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

  • The minimum value is the smallest value, of 24.
  • The maximum value is the smallest value, of 56.
  • Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.
  • The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.
  • The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.
  • The interquartile range is of 50 - 29 = 21.

More can be learned about five number summaries at brainly.com/question/17110151

#SPJ1

3 0
2 years ago
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