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FromTheMoon [43]
3 years ago
6

2/3 x -9/8 x -4/5 x -1

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

-151/120x -1 or 1\120 × (-151x -120)

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True or false to begin an indirect proof, you assume the opposite of what you intend to prove is true
damaskus [11]

Answer:

true

Step-by-step explanation:

you must assume its false and if said statement leads to an impossibility then its proved to be true

7 0
3 years ago
Read 2 more answers
How to solve this? ​
nevsk [136]

Answer:

Answer of 17 is ㏒(x^{2}+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is  x = -㏒12/㏒8 and Answer of 39 is x = 5

Step-by-step explanation:

17. ㏒x + ㏒(x+15)

     Using property ㏒a + ㏒b = ㏒a×b

     ∴ ㏒x + ㏒(x+15)

        ㏒x×(x+15)

        ㏒(x^{2}+15x)

        The answer is ㏒(x^{2}+15x)

33. 2^(x-5) = 8

     2^(x-5) = 2^3

      Using property 2^a = 2^b

      Then a = b

     ∴x-5 = 3

       x = 8

      The answer is x = 8

35. 2^x = 10

    Taking log on both sides gives

     ㏒2^x = ㏒10

     x×㏒2 = ㏒10

     x = ㏒10/㏒2

    The answer is x = ㏒10/㏒2

37. 8^-x = 12

    Taking log on both sides gives

     ㏒8^-x = ㏒12

     -x×㏒8 = ㏒12

      x = -㏒12/㏒8

    The answer is  x = -㏒12/㏒8

39. 5(2^3 × x) = 8

      5(8×x) = 8

      x = 5

    The answer is x=5

 

5 0
3 years ago
Can you help me with 6?
Paul [167]

Answer:

Less then

Step-by-step explanation:

When you dived by a decimal the answer decreases.

3 0
3 years ago
Read 2 more answers
For equations of the form y = a^x, where a is a constant, what is true about a if the y-values change little for small values of
fredd [130]
It is greater than 1

I hope this helps! I'm also more than happy to elaborate if you want :)
8 0
3 years ago
Joe wants to rent an apartment with an initial monthly rent of $1,400. He has been told that the landlord raises the rent 1.25%
nadya68 [22]

Answer: his pay for the 4th year is $1453.16

Step-by-step explanation:

The landlord raises the rent 1.25% each year. It means that the rent is increasing in geometric progression.

The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a = $1,400

r = 1 + 1.25/100 = 1.0125

n = 4 years

The 4th term(year), T4 is

T4 = 1400 × 1.0125^(4 - 1)

T4 = 1400 × 1.0125^3

T4 = $1453.16

8 0
3 years ago
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