y=mx+c
I picked the points (0, -4) and (-2,-10) to find the gradient of the line
M= rise/run
= 6/2
=3
Y-intercept is at - 4
Y= 3x - 4 is equation of the line given
Reciprocal of 3 is 1/3
(m1 x m2 = - 1)
So, to make - 1, our second gradient should be negative.
Gradient of the perpendicular line will be - 1/3
Y= - 1/3x + c
Substitute value of x & y into the equation
(-6,6) means x = - 6, y = 6
y = - 1/3x +c
6 = - 1/3 x - 6 + c
6 = 2 + c
-2
4 = c
Thus, final equation we're after will be:
y= - 1/3x + 4
Hope this helps!
