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2 years ago

12

How many degrees are in EACH angle of a REGULAR 8-sided polygon? (Hint - Do the triangle trick) (Hint - Remember your definition

of a regular polygon)

1 answer:

marishachu [46]2 years ago

6 0

Answer:

135

Step-by-step explanation:

interior angles sum=(n-2)x180

8 interior angles

(8-2)x180=1080

1080/8=135

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Without using a calculator convert the decimal into a fraction<br> 0. 75

mojhsa [17]

Step-by-step explanation:

Decimals can always be put over 1, as they're part of a whole number.

$\frac{0.75}{1}$

<u>Multiply both numerator and denominator by 100:</u>

<u /> $\frac{0.75 \times 100}{1\times 100} =\frac{75}{100}$

$\frac{0.75}{1} \: and \: \frac{75}{100} \: are \: fractions \: of \: 0.75$

3 0

2 years ago

PLEASE HELP ME !! WILL GIVE BRAINLIEST!!

PolarNik [594]

B is a times b
C is also a times b

sorry im stuck on the rest

6 0

3 years ago

The X multiple answers are 60 or 55 or 9 or 27 and

Molodets [167]

Step-by-step explanation:

It is an isosceles triangle , it has two equal angles both 55°.

All Isosceles triangles have two equal angles <em>a</em><em>n</em><em>d</em> two equal sides.

So in this case x +18 is equal to 3x, and to find x you will equal them to each other to create a linear equation and solve.

x + 18 = 3x

x - 3x = -18

-2x = -18

× = -18 / -2

× = 9 <em>(</em><em>a</em><em>n</em><em>s</em><em>)</em><em> </em>

Hope I was able to help. Good Luck :)))

5 0

2 years ago

Graph: g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2

Tatiana [17]

$g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2$

generate by: Amplitude:5 Period:4

Phase shift:(3 to the right) Vertical shift:-2

x=3,g(x)= 3

x=4,g(x)= -2

x=5,g(x)= -5

x=6,g(x)= -2

x=7,g(x)= 3

the graph is like cos(x)

learn more about trigonometric graphs here:

brainly.com/question/18265536

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3 0

1 year ago

A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par

sasho [114]

The velocity of the particle is given by

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

Since $a(t)=-4\sin2t$ and $v(0)=7$ , we get

$\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2$

$\implies v(t)=2\cos2t+5$

Similarly, the position function is obtained via

$x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du$

We know $v(t)$ and we're told that $x(0)=0$ , so

$\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t$

$\implies x(t)=\sin2t+5t$

making the answer A.

3 0

2 years ago