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2 years ago

12

How many degrees are in EACH angle of a REGULAR 8-sided polygon? (Hint - Do the triangle trick) (Hint - Remember your definition

of a regular polygon)

1 answer:

marishachu [46]2 years ago

6 0

Answer:

135

Step-by-step explanation:

interior angles sum=(n-2)x180

8 interior angles

(8-2)x180=1080

1080/8=135

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Solve the equation. 7+6=-3y+26<br> A. y= -8<br> B. y= -5<br> C. y= 5<br> D. y= 8

Umnica [9.8K]

The correct answer is c y=5

7 0

2 years ago

Two possible solutions of are -7 and 1. Which statement is true?

quester [9]

We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.

√11 - 2(-7) = √(-7)^2 + 4(-7) + 4

√25 = √25

5 = 5

The first solution, -7, makes the equation true, and so it is not extraneous.

√11 - 2(1) = √(1)^2 + 4(1) + 4

√9 = √9

3 = 3

The second solution, 1, makes the equation true, and so it is also not extraneous.

<h3>The correct option is D, neither solution is extraneous. </h3>

4 0

2 years ago

3p + 7 = -4(4 - 6p) + 2

zvonat [6]

p=1

Step-by-step explanation:

$3p + 7 = - 4(4 - 6p) + 2 \\ 3p + 7 = - 16 + 24p + 2 \\ 3p - 24p = - 16 + 2 - 7 \\ - 21p = - 21$

$\frac{ - 21p}{ - 21} = \frac{ - 21}{ - 21} \\ p = 1$

3 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!! Please

Arturiano [62]

Probability helps us to know the chances of an event occurring. There are six possible outcomes.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

$\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

A.) The outcomes that are possible from the first spinner is 1, 2, and 3, while the outcomes possible from the second spinner are 2, Red and blue.

All the possible outcomes from this two spinner are,

(B,1), (B,2), (B,3), (R,1), (R,2), and (R,3).

Hence, there are six possible outcomes.

B.) The letters that can be used are A and B. The numbers that can be used are 1, 2, 3, and 4.

All the possible out comes are,

(B,1), (B,2), (B,3)(B,4), (A,1), (A,2), (A,3), and (A,4).

Learn more about Probability:

brainly.com/question/795909

#SPJ1

3 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago