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Molodets [167]
3 years ago
12

How many degrees are in EACH angle of a REGULAR 8-sided polygon? (Hint - Do the triangle trick) (Hint - Remember your definition

of a regular polygon)​
Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

135

Step-by-step explanation:

interior angles sum=(n-2)x180

8 interior angles

(8-2)x180=1080

1080/8=135

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For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3? three-sevenths seven-thir
vova2212 [387]

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k can be written as,

xy=k\\\\(7) \times (3 ) =k\\\\k= 21

Hence, the value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

Learn more about Equation:

brainly.com/question/2263981

4 0
2 years ago
How can you use unit rates in multiplication to solve for missing measures and equivalent ratio problems?
geniusboy [140]
By viewing equivalent ratios and rates as deriving from, and extending, pairs of rows (or columns) in the multiplication table and by analyzing simple drawings that indicate the relative size of quantities.
6 0
3 years ago
In the morning a farm worker packed 4 pints of strawberries every 6 minutes.In the afternoon she packed 1 pint of strawberries e
RideAnS [48]

Answer:

20 pints per hour

Step-by-step explanation:

60/6 = 10

10 x 4 = 40

40 pints/hour in the morning

60/3 = 20

20 x 1 =20

20 pints/hour in the afternoon

40 - 20 = 20

20 pint/hour difference

4 0
3 years ago
What is<br> 5x + 20 = 5x + ??
IrinaK [193]

Answer:

??=20

Step-by-step explanation:

hope this helps

8 0
3 years ago
Read 2 more answers
Can you help me with this question.<br> 2a when a is equal to -3
solong [7]
2(-3) = -6, is the answer
5 0
3 years ago
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