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GenaCL600 [577]
3 years ago
9

What is the 8th term of the sequence 1, 3, 9, 27, 81,... .

Mathematics
1 answer:
slega [8]3 years ago
4 0

9514 1404 393

Answer:

  2187

Step-by-step explanation:

This geometric sequence has a first term of 1 and a common ratio of 3. Its general term can be written as ...

  an = a1·r^(n-1)

  an = 3^(n-1)

Then the 8th term is ...

  a8 = 3^(8-1) = 2187

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EFGH is a parallelogram. Find the measure of FG and EG <br>​
navik [9.2K]

Answer:

FG = 44

EG = 80

Step-by-step explanation:

For FG:

1) 5z - 16 = 3z + 8

2) 5z = 3z + 24

3) 2z = 24

4) z = 12

5) 3(12) + 8 = 44

For EG:

1) 2w + 22 = 4w + 4

2) 2w = 4w - 18

3) -2w = -18

4) w = 9

5) 4(9) + 4 + 2w + 22 = 80

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2 years ago
Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

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3 years ago
Simplify the expression by combining like terms. 16+8a−3a+6b−9
Svetradugi [14.3K]
7+5a+6b is the answer because 16-9 is 7 and 8-3 is 5.
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6047/18 will equal 335.94
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sorry again for asking this but can someone explain this and give me the answer. Been having a hard time learning this.
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3 years ago
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