Answer: 60
Step-by-step explanation:
Answer:
7) Mean = 48 8) Mean = 59.6 9) Mean = 31.6 10) Mean = 42.1
Median = 47.5 Median = 61 Median = 32 Median = 40
Mode = 72 Mode = 90 Mode = 46 Mode = 51
Range = 66 Range = 79 Range = 34 Range = 51
Step-by-step explanation:
This is a classic math problem, and it is not solved in a normal way.
<span>1+4=5
2+5=12
3+6=21
8+11=?
There is a pattern that can be spotted. 2+5 does not equal twelve, however 2*(2+5) does equal 12. Below is how to solve the rest of the equations:
</span>1+4=5 -> 1*(4+1)=5
2+5=12 -> 2*(5+1)=12
3+6=21 -> <span>3*(6+1)=21 </span>
8+11=? -> <span>8*(11+1)=96
</span>
This is one way to answer the problem, HOWEVER there is another way to answer the problem that gives the SAME answer, but many people mistakenly believes it gives a different answer. If anyone tries to post the other way of doing this problem, but tells you the answer is 40, please comment on this post or message me and let me know. I will explain why the answer is actually 96 either way.
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
