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2 years ago

How many solutions exist for the given equation 3x+13=3(x+6)+1 zero one two infinity many

Mathematics

2 answers:

Komok [63]2 years ago

8 0

Answer:

zero

Step-by-step explanation:

3x + 13 = 3(x + 6) + 1

3x + 13 = 3x + 18 + 1

3x - 3x = 18 + 1 - 13

0 = 18 + 1 - 13

0 = 6

NO SOLUTION

Helen [10]2 years ago

3 0

Answer:

Zero

Step-by-step explanation:

Given: 3x+13=3(x+6)+1

Step 1: Expand

3x+13=3x+19

Step 2: Subtract 3 from both sides

3x+13-13=3x+19-13

Step 3: Simplify

3x=3x+6

Step 4: Subtract 3x from both sides

3x-3x=3x-3x+6

Step 5: Simplify

0=6

NO REAL SOLUTIONS

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