First lets see how many combinations there are that make 8 from the numbers 1-6:
2+6
3+5
4+4
5+3
and 6+2.
Note: the order does matter, because you roll two die. This means the first die has a number and the second die also has a number. 2 on 1st dice and 6 on 2nd dice would be a different combination than 2 on 2nd dice and 6 on 1st dice.
Now we calculate the probability of getting a number 2 through 6 on the first dice: which is 5/6.
Then calculate the probability of getting a number that pairs up with the first number to make 8: *Note: once you get a number 2 through 6, there is only one other number that you can roll to make 8. This means the probability of getting a match would be 1/6 on the 2nd dice.
Finally, multiply the two fractions we got earlier: 5/6 x 1/6 = 5/36
Your probability would be 5/36 in fraction form, 13.89% in percent form, or 0.139 in decimal form rounded 3 places.
Hope this helps, and May the Force Be With You!
-Jabba the Hut
Answer:
-44ax^2-198x^2+66a+297
Step-by-step explanation:
there
Answer:
400+50+6
Step-by-step explanation:
456 means 400+50+6
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
