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satela [25.4K]
3 years ago
13

∠ABC measures 124° and ∠MNO measures 56°. Therefore, the two angles are

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0
Supplementary angles are angles that add up to 180 degrees.
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URGENT!!!! PLEASE SELECT ALL! IF YOU DO SO, YOU GET BRAINLIEST
dimulka [17.4K]

Uhhh I think it'd be C and... probably A or D. I'm not 100% sure, but if I was taking the test, that is what I would choose.

5 0
3 years ago
Multiply.
Kamila [148]
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
 | | | | x | - | 6
 | | 3 x^2 | + | 10 x | - | 1
 | | | | -x | + | 6
 | | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer:  3 x^3 - 8 x^2 - 61 x + 6 Thus B:
7 0
3 years ago
Write the equation of the line that has a slope of -2 and goes through the point (-3,4).
liubo4ka [24]

<u>SOLUTION:</u>

General Equation: y = mx + b

.

Substitute slope = -2 into the equation:

y = -2x + b

.

Find the y-intercept:

4 = -2(-3) + b

4 = 6 + b

b = -2

.

Substitute b = -2 into the equation:

y = -2x - 2

.

Answer: y = -2x - 2

4 0
3 years ago
Read 2 more answers
Find where the slope of the curve is defined:<br> x^2y-xy^2=4
Natali [406]
You do the implcit differentation, then solve for y' and check where this is defined. 
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0 
Solve for y': y'(x²-2xy) +2xy - y² = 0 
y' = (2xy-y²) / (x²-2xy) 
Check where defined: y' is not defined if the denominator becomes zero, i.e. 
x² - 2xy = 0 x(x - 2y) = 0 
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y: 
0^2*y - 0*y^2 =? 4 0 =? 4 
This is impossible, hence the function is not defined for 0, and we can disregard this. 
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16) 
This is a possible value for y, so we have a point where y is defined, but not y'. 
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-). 
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...). 
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function). 
3 0
3 years ago
Please help! it’s urgent
ycow [4]

Step-by-step explanation:

{9}^{ \frac{3}{2} }  \times  {27}^{ \frac{1}{2} }  =  {(3)}^{ \frac{3}{2} \times 2 }  \times  {(3)}^{ \frac{1}{2}  \times  3}  \\  =  {3}^{3}  \times  {3}^{ \frac{3}{2}  }  \\  =  {3}^{3 +  \frac{3}{2} }  \\  =  {3}^{4\frac{1}{2} }  \\  =  {3}^{ \frac{9}{2} }

8 0
3 years ago
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