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satela [25.4K]
3 years ago
13

∠ABC measures 124° and ∠MNO measures 56°. Therefore, the two angles are

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0
Supplementary angles are angles that add up to 180 degrees.
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What is 15/27 in a decimal?
amid [387]

Answer:

0.55555

Step-by-step explanation:

the 5 keeps repeating

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Find the measure of a.
Nostrana [21]

Answer:

50 degrees

Step-by-step explanation:

We know that an inscribed angle in a circle is 1/2 the arc that it inscribes. So, therefore the arc is inscribed by the 25 degrees is 50. Assuming that the center of the circle is O, the center angle will be the arc measure. Knowing this, angle a is 50 degrees. If you're curious about all these theorems, they can be proved using similar triangles.

fyi, using the same logic, angle b is 25 degrees

8 0
3 years ago
Assessment started: undefined.
SashulF [63]

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(x+4)

Step-by-step explanation:

6 0
3 years ago
The quadrilateral ABCD is a rhombus with BD = BC. On the side
Andreas93 [3]
The halves of the rhombus separated by line BD are equilateral triangles.
  ∠BAD = 60°
so
  ∠ADM is 0.80*60° = 48°.

∠BMD is an exterior angle to ΔAMD, so is equal to the sum
  ∠BMD = ∠BAD + ∠ADM
  = 60° +48° = 108°

∠BMD = 108°
5 0
3 years ago
PLEASE HELP 25 POINTS!!
eduard

Answer:

(27 y^(-8))/(4 x^6)

Step-by-step explanation:

Simplify the following:

(4 (3 x^2 y^4)^3)/(2 x^3 y^5)^4

Multiply each exponent in 2 x^3 y^5 by 4:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^(4×5))

4×5 = 20:

(4 (3 x^2 y^4)^3)/(2^4 x^(4×3) y^20)

4×3 = 12:

(4 (3 x^2 y^4)^3)/(2^4 x^12 y^20)

2^4 = (2^2)^2:

(4 (3 x^2 y^4)^3)/((2^2)^2 x^12 y^20)

2^2 = 4:

(4 (3 x^2 y^4)^3)/(4^2 x^12 y^20)

4^2 = 16:

(4 (3 x^2 y^4)^3)/(16 x^12 y^20)

Multiply each exponent in 3 x^2 y^4 by 3:

(4×3^3 x^(3×2) y^(3×4))/(16 x^12 y^20)

3×4 = 12:

(4×3^3 x^(3×2) y^12)/(16 x^12 y^20)

3×2 = 6:

(4×3^3 x^6 y^12)/(16 x^12 y^20)

3^3 = 3×3^2:

(4×3×3^2 x^6 y^12)/(16 x^12 y^20)

3^2 = 9:

(4×3×9 x^6 y^12)/(16 x^12 y^20)

3×9 = 27:

(4×27 x^6 y^12)/(16 x^12 y^20)

4/16 = 4/(4×4) = 1/4:

(27 x^6 y^12)/(4 x^12 y^20)

Combine powers. (27 x^6 y^12)/(4 x^12 y^20) = (27 x^(6 - 12) y^(12 - 20))/4:

(27 x^(6 - 12) y^(12 - 20))/4

6 - 12 = -6:

(27 x^(-6) y^(12 - 20))/4

12 - 20 = -8:

Answer: (27 y^(-8))/(4 x^6)

5 0
3 years ago
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