To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
120+24 divided by 8=
144 divided by 8= 18 because 18 times 8 equals 144
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.
The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius.
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2²
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.
Answer:
x=2.9
Step-by-step explanation:
3(3x+9)= -5-2x ( distribute)
9x+27= -5-2x (add 2x) (subtract 27)
11x= 32 ( divide by 11)
x= 2.9
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There cannot be more than two because there are only two vowels, e and a. But it has to be 4 lettered, which limits a lot of option, so there can only be one 4-letter code.