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3 years ago

Solve check for extraneous solutions (5x-4)^1/2-x=0 A. 1,5 B. 1,4 C. 0 D. 0,5

Mathematics

1 answer:

stira [4]3 years ago

3 0

Answer:

its actually 1,4 i just took the test and 1,5 is wrong

Step-by-step explanation:

the other guys an idiot

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5) Derek was surfing through the internet for a good deal on t-shirts. Help Derek find the

AlladinOne [14]

Answer:

The first one

Step-by-step explanation:

To figure out which one is the best deal, for each one how much one t-shirt costs.

First deal:

3 t-shirts for $28.95

To figure out how much money one t-shirt would cost, you divide $28.95 by 3.

1 t-shirt = 28.95/3 = $9.65.

Second deal:

4 t-shirts for $39

Same thing as the last one, except since there are 4 t-shirts you divide $39 by 4.

1 t-shirt = 39/4 = $9.75

Third deal:

5 t-shirts for $49.95

This time you will divide 49.95 by 5.

1 t-shirt = 49.95/5 = $9.99

The last step is to compare the three deals, and since you are trying to find the one that costs the least you can see that the first deal is the best one, because $9.65 per shirt is cheaper than $9.75 and $9.99

5 0

3 years ago

Divide (x^3+2x^2-x-2) by (x-1)

Ymorist [56]

$\frac{x^3+2x^2-x-2}{(x-1)} =x^2+3x+2 \\ \\ x^3+2x^2-x-2= \\= x^2(x+2)-(x+2) \\ =(x+2)(x^2-1)=(x+2)(x-1)(x+1) \\ \\ \frac{x^3+2x^2-x-2}{(x-1)} = \frac{(x+2)(x-1)(x+1)}{x-1} =(x+2)(x+1)=x^2+3x+2$

7 0

3 years ago

8x-5y= 14 – 5х+бу = -3

podryga [215]

Answer:

y= 34/23

x= 123/46

Step-by-step explanation:

Solve for x

8x-5y= 14

x= 14/8 +5/8y

Sub x into second equation

– 5х+бу = -3

-5(14/8 +5/8y) + 6y= -3

-29/4 +23/8y = -3

y= 34/23

Sub y into any equation and solve for x

8x=483/23

x= 123/46

4 0

3 years ago

Quickly answer number 10 text only no fonts (100 points) mark brainliest

Y_Kistochka [10]

There's no picture but soon as you add one so I can see what I'm answering then I will immediately help!

5 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago