Answer:
57/80L
Step-by-step explanation:
Given that the capacity (i.e maximum possible volume) of a pitcher is 9/10L
1st Pitcher is 3/8 full of milk
Hence Vol of milk in 1st pitcher = 9/10 x 3/8 = 27/80L
2nd Pitcher is 5/12 full of milk
Hence Vol of milk in 2nd pitcher = 9/10 x 5/12 = 3/8 = 30/80L
Total volume = 27/80 + 30/80 = 57/80L
6x +19
6(x +2) +7
distribute the 6 (multiply 6*x and 6*2)
6x + 12
add the 7 to the 12
=6x + 19
2.70×m=x
2.70 times the mile
17.5 or 35
because 350/10=35
350/12=17.5