Answer:
57/80L
Step-by-step explanation:
Given that the capacity (i.e maximum possible volume) of a pitcher is 9/10L
1st Pitcher is 3/8 full of milk
Hence Vol of milk in 1st pitcher = 9/10 x 3/8 = 27/80L
2nd Pitcher is 5/12 full of milk
Hence Vol of milk in 2nd pitcher = 9/10 x 5/12 = 3/8 = 30/80L
Total volume = 27/80 + 30/80 = 57/80L
Answer:A
x= -4
hope this helped :)
a² + b² = c²
a² + 9² = 12²
a² + 81 = 144
a² = 63
a = √63
