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alina1380 [7]
3 years ago
8

5,395 - 2,697 How do you solve?

Mathematics
2 answers:
Art [367]3 years ago
4 0

Answer:

you would subtract 2697 from 5395. you have it in the correct format. the answer would be 2,698.

Step-by-step explanation:

sashaice [31]3 years ago
3 0

Answer:

2698

Step-by-step explanation:First you take 1000 from 5000 and then distribute it to 395

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Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


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3 years ago
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Which of the following scenarios could be represented by the expression<br> 6x + 11y?
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Answer:

A

A

Step-by-step explanation:

A. I don't know hope I helped you out if not sorry for the wrong answer.

3 0
3 years ago
)The scatter plot shows the number of fliers mailed out in a month (in thousands) and the number of new customers small business
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Well...just look at ur graph...it appears that the more fliers u send out, the more customers there are....therefore,when the fliers are increased,  the number of new customers will increase because the graph shows a positive association
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2 years ago
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A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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