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almond37 [142]
2 years ago
13

Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answe

r. The apothem, rounded to the nearest tenth, is units. The perimeter of the equilateral triangle is units. Therefore, the area of the equilateral triangle is , or approximately 43. 5 units2. The calculated areas are.
Mathematics
2 answers:
8090 [49]2 years ago
7 0

The calculated areas of both are the same instead of using the different formulas that are 43. 5 squared unit.

<h3>What is the area of a regular polygon?</h3>

The area of the polygon is the product of half of the apothem of the triangle and perimeter.

The area of the polygon = \frac{1}{2} \times h \times p

The side of the triangle is 10 units.

Apothem of an equilateral triangle

s = \frac{\sqrt{3} a}{6}

s= \sqrt{3} \times 10/6

s = 2.88

Here, a is the side of the triangle.

Thus the apothem of the triangle is 2.9 units.

The perimeter of the equilateral triangle is equal to the three times the sides.

Perimeter of the equilateral triangle ,

P = 3(10)

P = 30

Therefore, the perimeter of the equilateral triangle is 30 units.

The area of the equilateral triangle-

The area of the polygon = \frac{1}{2} \times h \times p

A = 1/2 \times 2.9 \times 30

A = 43.5

Thus the area of the equilateral triangle is 43.5 squared units.

Therefore, The calculated areas of both are the same instead of using the different formulas.

Learn more about the apothem;

brainly.com/question/10580427

Lana71 [14]2 years ago
6 0

Answer:

(A) 2.9

(C)30

(A)1/2(2.9)(30)

(D)The same despite using different formulas

Step-by-step explanation:

I did it

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What is the solution of x=2+ square root x-2?
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So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

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Next, square both sides:

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Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

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Now you can rewrite the equation as (x-3)(x-2)=0

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Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

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Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

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